how to solve the

Towers Of Hanoi

There are some disks (with holes through the middle) on one of three rods.
You must move them to another rod one disk at a time,
but you can never place a larger disk on top of a smaller one.
The goal is to do it in the fewest possible moves.

To accomplish this with one disk takes one move.
To accomplish this with two disks takes three moves.
To accomplish this with three disks takes seven moves.
To accomplish this with four disks takes fifteen moves.
So, every time you add a disk you more than double the moves.

The formula would look like this (where D is disks and M is moves):
M = 2D - 1
In other words, the six disks shown require 63 moves. . . .

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